Using Advanced Generator Methods

I do not understand this statement in “infinite_palindromes” function. i = (yield num) num is yielding but yet in parentheses (generator expression)

Also, this whole loop is unclear to me. Can anyone explain or give me some pointer.

while True:
    if is_palindrome(num):
        i = (yield num)
        if i is not None:
            num = i
    num += 1

Hey everyone

Same as @zell0ss and @Howard M Sherman I didn’t understand why the code was not printing 11, 101, 1001 … so, doing some research and debugging this is what I found:

1. In the first loop, you’re yielding an object (num = 11), then you save the “result” of that yield operation, which is None (i == None), and then you yield that None. In the second loop, you yield an object (num = 101), then you save the “result” of that yield operation, but in this case you NEVER yield that result, so None does not appear in the output. in the third loop (num = 111) is happening the same that happens in the first one, this is, yielding the None result.
2. the way that I found to fix it is to add another yield statement. this yield statement is invoked only in the even loops, in order to yield the “None” result and print the correct number:

def infinite_palindromes():
    """
    Palindromes generator
    """
    num = 0
    while True:
        if is_palindrome(num):
            i = yield num
            yield num # this is the new line
            if i is not None:
                num = i
        num += 1

also I added a time delay in the for cycle to actually see the result because for some reason, works faster than the original code:

for i in gen_pal:
    time.sleep(1)
    print(i)
    digits = len(str(i))
    gen_pal.send(10 ** (digits))

Hopefully all this explanation can be helpful :)

It’s frustrating when it takes longer to understand the example than the concept being explained.

Why are we skipping to the next longer palindrome when we found the first for the current digit count? After 121 there are many more three-digit palindromes before we reach 1000. Why are we skipping them? Do we only want the first palindrome per digit count? If so, this deserves explicit mention.

Also, it’d be worth defining what exactly comprises a palindrome: According to the usual definition (“reads the same forward as backwards”), a one-digit number is a palindrome. This definition has the advantage to lend itself to recursive algorithms to detect palindromes.

Finally, these types of constructs:

    if num == reversed_num:
        return True
    else:
        return False

are more succinct and easier to read:

    return num == reversed_num

My inner Bash programmer asserted itself and I rewrote is_palindrome as:

is_palindrome = lambda val: int(''.join(reversed([x for x in str(val)]))) == val

This does count single digits as palindromes, but I can’t help liking it more :))

I just got an even better lambda from the realpython slack group!

is_palindrome = lambda x: str(x) == str(x)[::-1]

elegance += 20

I cannot understand why i = (yield num) for “num = 101” or “num = 1001”, sets i to None. It also seems that for these numbers, yield does not return to the generator consumer process. It is not explained at all in the course, though it’s critical to understand generators.

I found this tutorial little difficult to grasp. Checkout this resource for easy reading and better examples

hi i’m trying to return the generator expression from one function to another

def infinite_seq(n):
  k=(num**2 for num in range(n))
  print(type(k)). ->generator 
  return k
def calling():
  r=(infinite_seq(5))
  print(type(r)) ->generator
  n=list(r)
  print(n)
 c=calling()

here my question is how to view the r value in better way rather than converting it to list . note:when i’m trying to use r=next(infinite_seq(5)) it is printing 0

Not clear at all what happens in the while after the send() and why it jumps the first palindrome after 100, 1000, 10000 and so on, which should be that value +1, to the next palindromes which are 111, 1111, 10101 and so on.

@Ray Hey, I’m not sure if I understand your doubts, but I’ll try to explain how this code works.

The yield expression in infinite_palindromes() does two things:

1. It suspends the generator and passes the current value of num to the for loop.
2. It waits for a new value to be supplied using .send(), which gets assigned to i. If .send() is not used, i remains None, and num just increments normally.

When you call .send(10 ** digits), the generator resumes execution right after the last yield, assigning 10 ** digits to a local variable called i. Since i is not None, num is updated to this new value, effectively skipping all numbers between the last palindrome and 10 ** digits.

This explains why certain expected palindromes are skipped. For example, after yielding 99, .send(100) makes num = 100, but the generator increments it immediately, skipping 101 and moving toward the next palindrome, like 111.

I’d recommend stepping through this code line by line using a debugger built into your code editor or IDE to get a better understanding of how this code works.