# Convert Fahrenheit to Celsius

**00:00**
The second part of the challenge is very similar to the first one, only the other way around. So this time the function is `convert_far_to_cel()`

with a parameter named `temp_far`

because you need the Fahrenheit temperature as an argument when you call the function.

**00:18**
And then again, you can take the formula from above, but this time the parentheses are super-duper important because you need to subtract the `32`

from the `temp_far`

variable first before you multiply by `5 / 9`

because of the arithmetic rules of which comes first.

**00:42**
Otherwise, you would multiply the `32`

with `5 / 9`

, and you don’t want this. So first you need to separate the `32`

from `temp_far`

.

**00:52**
And then again you can decide if you want to put parentheses around `5 / 9`

in the end and if you want to put a space in there so the slash stands alone,

**01:04**
and in the end, you return `temp_cel`

.

**01:09**
The function looks a bit different. Only the formula inside is a different one. And when you call `convert_far_to_cel()`

with the argument `72`

,

**01:21**
then the function returns `22.222222`

and so on. So there is a similar situation like before. There are a bunch of integers after the dot, but the rounding will be tackled in one of the next lessons.

**01:38**
But now that you got the `convert_far_to_cel()`

function, you can actually check the `98.6`

from before.

**01:46**
Perfect. It converts to `37`

Celsius. So the function works as expected.

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