Break Out of the Pattern (Solution)

Here’s my version of this exercise:

while True:
    text = str(input("Enter input: "))
    if text == "q" or text == "Q":
        break
    else:
        continue

@Learner nice, this works! However, your else block isn’t necessary because a while True loop will continue to loop anyways, so you only need to define the break condition.

Here is my version, albeit a little bit long, instead of the break, i decided to make the exit condition as a boolean expression for the while loop

exit_prompts = ('q', 'Q')
message = 'You are trapped, find a way to exit!'
tries = 1
max_tries = 6

print(f'{message}\nYou have {max_tries} tries, use it wisely!')
while (answer := input('>>> ') not in exit_prompts):
    max_tries -= 1

    if tries < 3:
        print('\nnu-huh, keep trying!\tTries left:', max_tries)
    elif tries < 6:
        print('\nYou can do it!\tTries left:', max_tries)
    else:
        print('\nThe secret untrap me prompt was \'q\' or \'Q\'')
        print('You are now untrapped :)')
        break

    tries += 1
else:
    print('GOOD JOB! Here is a cookie :D')

Here is my code.

letter_added = True

while letter_added == True:
    user_input = input("Enter a letter: ")
    if user_input != "Q" and user_input != "q":
        letter_added == True
    else:
        letter_added == False
        break

I learned a few things from this exercise. First, I originally had letter_added == True in which I got a name undefined error. Then I had if user_input != "Q" or "q" instead of above, and it didn’t the program prompted for a letter even "q" and "Q".

I don’t know how my code was formatted this way – this is not the way it looked when I posted it. Sorry.

I tried to enter the code again, manually, but I got the same format as above. What am I doing wrong?

Hi @ajackson54, I edited your code formatting so that it looks like you intended. You can create such fenced code blocks using backticks, and you can even add syntax highlighting.

As for your code solution, I think it’s mostly a well readable solution that makes use of a flag via the letter_added variable. I’d still suggest to slim it down a bit. You don’t need to continue setting letter_added = True in the case that the user didn’t choose the exit condition. In that case, it’s still True!

letter_added = True

while letter_added == True:
    user_input = input("Enter a letter: ")
    if user_input == "Q" or user_input == "q":
        break

I also changed your comparison operators from != to ==, and your boolean logic from and to or. Do these changes make sense to you? Why do you think I applied them?

Yes, your code is a lot cleaner. Also, I don’t really need the “==True” after letter_added. As for changing from != to ==, I would guess it would be faster in the loop.